integral from-3 to 0 of g(t)

Lösung

\int_{- 3}^{0} g (t) d t

- \frac{9 g}{2}

Schritte zur Lösung

\int_{- 3}^{0} g t d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{- 3}^{0} t d t

Wende die Potenzregel an

= g [\frac{t ^{2}}{2}]_{- 3}^{0}

Berechne die Grenzen:

- \frac{9}{2}

= g (- \frac{9}{2})

Vereinfache

= - \frac{9 g}{2}

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