integral from 0 to pi of 2cos^4(x)sin(x)

Lösung

\int_{0}^{π} 2 cos^{4} (x) sin (x) d x

\frac{4}{5}

Dezimale

0.8

Schritte zur Lösung

\int_{0}^{π} 2 cos^{4} (x) sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{π} cos^{4} (x) sin (x) d x

Wende U-Substitution an

= 2 \cdot \int_{1}^{- 1} - u^{4} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= 2 (- \int_{- 1}^{1} - u^{4} d u)

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 (- (- \int_{- 1}^{1} u^{4} d u))

Wende die Potenzregel an

= 2 (- (- [\frac{u ^{5}}{5}]_{- 1}^{1}))

Vereinfache

= 2 [\frac{u ^{5}}{5}]_{- 1}^{1}

Berechne die Grenzen:

\frac{2}{5}

= 2 \cdot \frac{2}{5}

Vereinfache

= \frac{4}{5}

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