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人気のある微分積分 >

integral from 0 to 2 of |x-2|

解

\int_{0}^{2} ∣ x - 2 ∣ d x

解

2

解答ステップ

\int_{0}^{2} ∣ x - 2 ∣ d x

絶対数を排除する

= \int_{0}^{2} - x + 2 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} x d x + \int_{0}^{2} 2 d x

\int_{0}^{2} x d x = 2

\int_{0}^{2} 2 d x = 4

= - 2 + 4

簡素化

= 2

グラフ

人気の例

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integral from 0 to 1 of 1/(sqrt(3x+1))

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