integral from-1 to 2 of 2x-1

Lösung

\int_{- 1}^{2} 2 x - 1 d x

0

Schritte zur Lösung

\int_{- 1}^{2} 2 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 x d x - \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} 2 x d x = 3

\int_{- 1}^{2} 1 d x = 3

= 3 - 3

Vereinfache

= 0

\int_{0}^{3} \frac{5}{3 x + 1} d x

\int_{1}^{4} 63 x^{\frac{5}{2}} d x

\int_{2}^{2} g (x) d x

\int_{1}^{3} (\frac{x ^{2} + 4}{x}) d x

\int_{1}^{3} (\frac{x ^{2} - 1}{4 x ^{2}}) d x