integral from 1 to 5 of x^3+8x-4

Lösung

\int_{1}^{5} x^{3} + 8 x - 4 d x

236

Schritte zur Lösung

\int_{1}^{5} x^{3} + 8 x - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{3} d x + \int_{1}^{5} 8 x d x - \int_{1}^{5} 4 d x

\int_{1}^{5} x^{3} d x = 156

\int_{1}^{5} 8 x d x = 96

\int_{1}^{5} 4 d x = 16

= 156 + 96 - 16

Vereinfache

= 236

\int_{3}^{4} 2 x^{2} d x

\int_{- 1}^{1} 3 x^{5} ∣ x ∣ d x

\int_{0}^{1} \frac{1}{100 + x ^{2}} d x

\int_{1}^{16} 2 x^{- \frac{3}{2}} d x

\int_{1}^{4} x x^{2} + 1 d x