What is the integral from 0 to 2pi of 16 ?

The integral from 0 to 2pi of 16 is 32pi

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integral from 0 to 2pi of 16

\int_{0}^{2 π} 16 d x

32 π

Decimal

100.53096 \dots

Solution steps

\int_{0}^{2 π} 16 d x

Integral of a constant:

\int a d x = a x

= [16 x]_{0}^{2 π}

Compute the boundaries:

32 π

= 32 π

\int_{0}^{t} \frac{1}{x ^{2} + 1} d x

\int_{x}^{1} 3 x d x

\int_{1}^{\infty} x^{- 6} d x

\int_{0}^{1} x (1 + x) d x

\int_{1}^{3} π (\frac{1}{x})^{2} d x

What is the integral from 0 to 2pi of 16 ?
The integral from 0 to 2pi of 16 is 32pi