integral of 3sin(4x)+4sin(3x)

Lösung

\int 3 sin (4 x) + 4 sin (3 x) d x

- \frac{3}{4} cos (4 x) - \frac{4}{3} cos (3 x) + C

Schritte zur Lösung

\int 3 sin (4 x) + 4 sin (3 x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 sin (4 x) d x + \int 4 sin (3 x) d x

\int 3 sin (4 x) d x = - \frac{3}{4} cos (4 x)

\int 4 sin (3 x) d x = - \frac{4}{3} cos (3 x)

= - \frac{3}{4} cos (4 x) - \frac{4}{3} cos (3 x)

Füge eine Konstante zur Lösung hinzu

= - \frac{3}{4} cos (4 x) - \frac{4}{3} cos (3 x) + C

\frac{d}{d x} (x^{5} e^{x} cos (x))

in v erse l a pl a ce \frac{s - 3}{s ^{2} + 10 s + 9}

x \to 4 lim (2 x + 1)

d er i v a t i v e \frac{( x ^{8} )}{8 ( 1 - x ^{2} ) ^{4}}

\frac{d}{d x} (\frac{1}{( 9 + x ) ^{2}})