integral from 4 to 16 of 1/(sqrt(z))

Lösung

\int_{4}^{16} \frac{1}{z} d z

4

Schritte zur Lösung

\int_{4}^{16} \frac{1}{z} d z

Wende die Potenzregel an

= [2 z^{\frac{1}{2}}]_{4}^{16}

Wende Radikal Regel an:

a^{\frac{1}{n}} = n a

= [2 z]_{4}^{16}

Berechne die Grenzen:

4

= 4

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