integral from 2 to 4 of (1+x)

Lösung

\int_{2}^{4} (1 + x) d x

8

Schritte zur Lösung

\int_{2}^{4} 1 + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} 1 d x + \int_{2}^{4} x d x

\int_{2}^{4} 1 d x = 2

\int_{2}^{4} x d x = 6

= 2 + 6

Vereinfache

= 8

\int_{- \frac{π}{3}}^{0} (sin (x)) d x

\int_{1}^{5} \frac{1}{( 10 - x ) ^{2}} d x

\int_{- 5}^{10} 5 - ∣ x ∣ d x

\int_{1}^{4} x - 1 d x

\int_{0}^{x^{2}} \frac{1}{3 + x ^{3}} d y