integral from 1 to-2 of (2x-1)

Lösung

\int_{1}^{- 2} (2 x - 1) d x

6

Schritte zur Lösung

\int_{1}^{- 2} 2 x - 1 d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 2}^{1} 2 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int_{- 2}^{1} 2 x d x - \int_{- 2}^{1} 1 d x)

\int_{- 2}^{1} 2 x d x = - 3

\int_{- 2}^{1} 1 d x = 3

= - (- 3 - 3)

Vereinfache

= 6

\int_{x}^{0} e^{- 16 t} d t

\int_{0}^{1} e^{x^{2}} x^{3} d x

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\int_{1}^{\infty} x \frac{3}{x ^{4}} d x