integral from 3 to 5 of 6t-18

Lösung

\int_{3}^{5} 6 t - 18 d t

12

Schritte zur Lösung

\int_{3}^{5} 6 t - 18 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{3}^{5} 6 t d t - \int_{3}^{5} 18 d t

\int_{3}^{5} 6 t d t = 48

\int_{3}^{5} 18 d t = 36

= 48 - 36

Vereinfache

= 12

\int_{- 1}^{1} (x^{2} + y^{2}) d y

\int_{- 3}^{4} (10 - 5 x) d x

\int_{1}^{2} x \cdot e^{x} d x

\int_{0}^{1} \frac{e ^{\frac{1}{x}}}{x ^{2}} d x

\int_{1}^{3} 2 x d x