integral from 1 to 3 of (4x+1)

Lösung

\int_{1}^{3} (4 x + 1) d x

18

Schritte zur Lösung

\int_{1}^{3} 4 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 4 x d x + \int_{1}^{3} 1 d x

\int_{1}^{3} 4 x d x = 16

\int_{1}^{3} 1 d x = 2

= 16 + 2

Vereinfache

= 18

\int_{0}^{π} - x d x

\int_{0}^{3} 3 x^{2} - x^{3} d x

\int_{- 6}^{3} \frac{3}{x ^{2}} d x

\int_{2}^{7} \frac{4 x}{x ^{2} + 1} d x

\int_{y}^{x} \frac{1}{x} d x