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人気のある微分積分 >

integral from 1 to 2 of 20x^3+6/(x^2)

解

\int_{1}^{2} 20 x^{3} + \frac{6}{x ^{2}} d x

解

78

解答ステップ

\int_{1}^{2} 20 x^{3} + \frac{6}{x ^{2}} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 20 x^{3} d x + \int_{1}^{2} \frac{6}{x ^{2}} d x

\int_{1}^{2} 20 x^{3} d x = 75

\int_{1}^{2} \frac{6}{x ^{2}} d x = 3

= 75 + 3

簡素化

= 78

グラフ

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