integral from 0 to 5 of ze^{-z}

Lösung

\int_{0}^{5} z e^{- z} d z

- \frac{6}{e ^{5}} + 1

Dezimale

0.95957 \dots

Schritte zur Lösung

\int_{0}^{5} z e^{- z} d z

Wende die partielle Integration an

= [- e^{- z} z - \int - e^{- z} d z]_{0}^{5}

\int - e^{- z} d z = e^{- z}

= [- e^{- z} z - e^{- z}]_{0}^{5}

Berechne die Grenzen:

- \frac{6}{e ^{5}} + 1

= - \frac{6}{e ^{5}} + 1

\int_{1}^{2} ln (2 x) - ln (x) d x

\int_{0}^{5} h (x) d x

\int_{- 1}^{2} (5 x - 5) d x

\int_{- 1}^{0} (e^{x}) d x

\int_{0}^{\infty} e^{- s} d s