integral from 1 to 4 of (x-9)/(sqrt(x))

Lösung

\int_{1}^{4} \frac{x - 9}{x} d x

- \frac{40}{3}

Dezimale

- 13.33333 \dots

Schritte zur Lösung

\int_{1}^{4} \frac{x - 9}{x} d x

Multipliziere aus

\frac{x - 9}{x} : x - \frac{9}{x}

= \int_{1}^{4} x - \frac{9}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x d x - \int_{1}^{4} \frac{9}{x} d x

\int_{1}^{4} x d x = \frac{14}{3}

\int_{1}^{4} \frac{9}{x} d x = 18

= \frac{14}{3} - 18

Vereinfache

\frac{14}{3} - 18 : - \frac{40}{3}

= - \frac{40}{3}

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