integral from 1 to 7 of-1/7 x+1

Lösung

\int_{1}^{7} - \frac{1}{7} x + 1 d x

\frac{18}{7}

Dezimale

2.57142 \dots

Schritte zur Lösung

\int_{1}^{7} - \frac{1}{7} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{7} \frac{1}{7} x d x + \int_{1}^{7} 1 d x

\int_{1}^{7} \frac{1}{7} x d x = \frac{24}{7}

\int_{1}^{7} 1 d x = 6

= - \frac{24}{7} + 6

Vereinfache

- \frac{24}{7} + 6 : \frac{18}{7}

= \frac{18}{7}

\int_{3}^{4} (x^{2} + x - 12) d x

\int_{1}^{2} x + 6 d x

\int_{- 2}^{4} 4 d x

\int_{0}^{2} 4 x e^{- 2 x} d x

\int_{0}^{1} (\frac{5}{7 + 7 x ^{2}}) d x