integral from 2 to 3 of 1-4/(x^2)

Lösung

\int_{2}^{3} 1 - \frac{4}{x ^{2}} d x

\frac{1}{3}

Dezimale

0.33333 \dots

Schritte zur Lösung

\int_{2}^{3} 1 - \frac{4}{x ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} 1 d x - \int_{2}^{3} \frac{4}{x ^{2}} d x

\int_{2}^{3} 1 d x = 1

\int_{2}^{3} \frac{4}{x ^{2}} d x = \frac{2}{3}

= 1 - \frac{2}{3}

Vereinfache

1 - \frac{2}{3} : \frac{1}{3}

= \frac{1}{3}

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