integral from 0 to 2 of f(3x)

Lösung

\int_{0}^{2} f (3 x) d x

6 f

Schritte zur Lösung

\int_{0}^{2} f \cdot 3 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 f \cdot \int_{0}^{2} x d x

Wende die Potenzregel an

= 3 f [\frac{x ^{2}}{2}]_{0}^{2}

Berechne die Grenzen:

2

= 3 f \cdot 2

Vereinfache

= 6 f

\int_{0}^{1} (2 - 3 x)^{4} d x

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