integral from 200 to 300 of-0.1x+40

解答

\int_{200}^{300} - 0.1 x + 40 d x

1500

求解步骤

\int_{200}^{300} - 0.1 x + 40 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{200}^{300} 0.1 x d x + \int_{200}^{300} 40 d x

\int_{200}^{300} 0.1 x d x = 2500

\int_{200}^{300} 40 d x = 4000

= - 2500 + 4000

化简

= 1500

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