What is the integral from 0 to infinity of 9e^{-3x} ?

The integral from 0 to infinity of 9e^{-3x} is 3

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integral from 0 to infinity of 9e^{-3x}

\int_{0}^{\infty} 9 e^{- 3 x} d x

3

Solution steps

\int_{0}^{\infty} 9 e^{- 3 x} d x

Compute the indefinite integral:

\int 9 e^{- 3 x} d x = - 3 e^{- 3 x} + C

Compute the boundaries:

\int_{0}^{\infty} 9 e^{- 3 x} d x = 0 - (- 3)

= 0 - (- 3)

Simplify

= 3

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What is the integral from 0 to infinity of 9e^{-3x} ?
The integral from 0 to infinity of 9e^{-3x} is 3