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Popular Calculus >

integral from-1 to 1 of-x+1

Solution

\int_{- 1}^{1} - x + 1 d x

Solution

2

Solution steps

\int_{- 1}^{1} - x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{1} x d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 1 d x = 2

= - 0 + 2

Simplify

= 2

Graph

Popular Examples

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\int_{0}^{π} (sec (x))^{2} d x

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\int_{0}^{15} \frac{x}{( 1 + x ) ^{\frac{3}{4}}} d x

integral from-8 to 1 of-x^2-3x

\int_{- 8}^{1} - x^{2} - 3 x d x

integral from 0 to 3 of te^{-0.5t}

\int_{0}^{3} t e^{- 0.5 t} d t

integral from 0 to 9 of 1000x+250

\int_{0}^{9} 1000 x + 250 d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of-x+1 ?
The integral from-1 to 1 of-x+1 is 2