integral from-6 to 4 of sqrt(24-2x-x^2)

Lösung

\int_{- 6}^{4} 24 - 2 x - x^{2} d x

\frac{25 π}{2}

Dezimale

39.26990 \dots

Schritte zur Lösung

\int_{- 6}^{4} 24 - 2 x - x^{2} d x

Vervollständige das Quadrat

24 - 2 x - x^{2} : - (x + 1)^{2} + 25

= \int_{- 6}^{4} - (x + 1)^{2} + 25 d x

Wende U-Substitution an

= \int_{- 5}^{5} - u^{2} + 25 d u

Trigonometrische Substitution anwenden

= \int_{- \frac{π}{2}}^{\frac{π}{2}} 25 cos^{2} (v) d v

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 25 \cdot \int_{- \frac{π}{2}}^{\frac{π}{2}} cos^{2} (v) d v

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= 25 \cdot \int_{- \frac{π}{2}}^{\frac{π}{2}} \frac{1 + cos ( 2 v )}{2} d v

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 25 \cdot \frac{1}{2} \cdot \int_{- \frac{π}{2}}^{\frac{π}{2}} 1 + cos (2 v) d v

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 25 \cdot \frac{1}{2} (\int_{- \frac{π}{2}}^{\frac{π}{2}} 1 d v + \int_{- \frac{π}{2}}^{\frac{π}{2}} cos (2 v) d v)

\int_{- \frac{π}{2}}^{\frac{π}{2}} 1 d v = π

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos (2 v) d v = 0

= 25 \cdot \frac{1}{2} (π + 0)

Vereinfache

25 \cdot \frac{1}{2} (π + 0) : \frac{25 π}{2}

= \frac{25 π}{2}

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