integral from 0 to 2 of (x^4-8x)

Lösung

\int_{0}^{2} (x^{4} - 8 x) d x

- \frac{48}{5}

Dezimale

- 9.6

Schritte zur Lösung

\int_{0}^{2} x^{4} - 8 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{4} d x - \int_{0}^{2} 8 x d x

\int_{0}^{2} x^{4} d x = \frac{32}{5}

\int_{0}^{2} 8 x d x = 16

= \frac{32}{5} - 16

Vereinfache

\frac{32}{5} - 16 : - \frac{48}{5}

= - \frac{48}{5}

\int_{- 1}^{2} (2 - x) d x

\int_{- 2}^{2} \frac{x ^{3}}{1 + x ^{2}} d x

\int_{0}^{l n (x)} y e^{z} d z

\int_{2}^{10} \frac{1}{12} d x

\int_{- 5}^{3} \frac{x ^{3} - 2 x + 45}{2} d x