What is the integral of 12x^2+6x-5 ?

The integral of 12x^2+6x-5 is 4x^3+3x^2-5x+C

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integral of 12x^2+6x-5

\int 12 x^{2} + 6 x - 5 d x

4 x^{3} + 3 x^{2} - 5 x + C

Solution steps

\int 12 x^{2} + 6 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{2} d x + \int 6 x d x - \int 5 d x

\int 12 x^{2} d x = 4 x^{3}

\int 6 x d x = 3 x^{2}

\int 5 d x = 5 x

= 4 x^{3} + 3 x^{2} - 5 x

Add a constant to the solution

= 4 x^{3} + 3 x^{2} - 5 x + C

\int_{0}^{\frac{π}{4}} tan^{8} (θ) sec^{2} (θ) d θ

\frac{e ^{x}}{ln ( x )}

\frac{d}{d x} (x t)

x \to - 2 - lim (\frac{1}{x - 2})

\frac{d}{d x} ((3 x^{4} - 4) (3 - 2 x^{3}))

What is the integral of 12x^2+6x-5 ?
The integral of 12x^2+6x-5 is 4x^3+3x^2-5x+C