integral from-2 to 2 of (x+1)

Lösung

\int_{- 2}^{2} (x + 1) d x

4

Schritte zur Lösung

\int_{- 2}^{2} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} x d x + \int_{- 2}^{2} 1 d x

\int_{- 2}^{2} x d x = 0

\int_{- 2}^{2} 1 d x = 4

= 0 + 4

Vereinfache

= 4

\int_{0}^{2} (4 x - 2) d x

\int_{- 4 π}^{π} cos^{2} (x) d x

\int_{- 1}^{2} \frac{1}{( 2 + 3 x ) ^{3}} d x

\int_{0}^{π} - x cos (x) d x

\int_{- 2}^{1} (2 t^{2} - 1)^{2} d t