integral from-2 to-1 of 3x-9

解答

\int_{- 2}^{- 1} 3 x - 9 d x

- \frac{27}{2}

十进制

- 13.5

求解步骤

\int_{- 2}^{- 1} 3 x - 9 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} 3 x d x - \int_{- 2}^{- 1} 9 d x

\int_{- 2}^{- 1} 3 x d x = - \frac{9}{2}

\int_{- 2}^{- 1} 9 d x = 9

= - \frac{9}{2} - 9

化简

- \frac{9}{2} - 9 : - \frac{27}{2}

= - \frac{27}{2}

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