integral from 1 to 8 of 1+x^3

解答

\int_{1}^{8} 1 + x^{3} d x

\frac{4123}{4}

十进制

1030.75

求解步骤

\int_{1}^{8} 1 + x^{3} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{8} 1 d x + \int_{1}^{8} x^{3} d x

\int_{1}^{8} 1 d x = 7

\int_{1}^{8} x^{3} d x = \frac{4095}{4}

= 7 + \frac{4095}{4}

化简

7 + \frac{4095}{4} : \frac{4123}{4}

= \frac{4123}{4}

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