integral from 0 to 2 of 6-3x

Lösung

\int_{0}^{2} 6 - 3 x d x

6

Schritte zur Lösung

\int_{0}^{2} 6 - 3 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 6 d x - \int_{0}^{2} 3 x d x

\int_{0}^{2} 6 d x = 12

\int_{0}^{2} 3 x d x = 6

= 12 - 6

Vereinfache

= 6

\int_{0}^{1} 2^{3 x} d x

\int_{4.6}^{7} 12 x^{2} - 6 x + \frac{4}{x} d x

\int_{0}^{l n (3)} \frac{x}{x ^{2} - 3 x} d x

\int_{- 1}^{1} \frac{12}{1 + x ^{2}} d x

\int_{0}^{π} \frac{7}{3} sin (x) d x