What is the integral from 2 to 4 of e^{x^2} ?

The integral from 2 to 4 of e^{x^2} is (sqrt(pi)\erfi(4)-sqrt(pi)\erfi(2))/2

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integral from 2 to 4 of e^{x^2}

\int_{2}^{4} e^{x^{2}} d x

\frac{π erfi ( 4 ) - π erfi ( 2 )}{2}

Solution steps

\int_{2}^{4} e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= [\frac{π}{2} erfi (x)]_{2}^{4}

Compute the boundaries:

\frac{π erfi ( 4 ) - π erfi ( 2 )}{2}

= \frac{π erfi ( 4 ) - π erfi ( 2 )}{2}

\int_{0}^{1} \frac{1}{( x + 1 ) ^{5}} d x

\int_{2}^{3} \frac{x ^{2}}{x ^{2} - 1} d x

\int_{0}^{4} x^{2} - 9 d x

\int_{0}^{1} 4 x^{2} + 1 x d x

\int_{4}^{5} 16 - x^{2} d x

What is the integral from 2 to 4 of e^{x^2} ?
The integral from 2 to 4 of e^{x^2} is (sqrt(pi)\erfi(4)-sqrt(pi)\erfi(2))/2