integral from 1 to 2 of 2x-2

Lösung

\int_{1}^{2} 2 x - 2 d x

1

Schritte zur Lösung

\int_{1}^{2} 2 x - 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x - \int_{1}^{2} 2 d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 2 d x = 2

= 3 - 2

Vereinfache

= 1

\int_{0}^{\frac{x}{2}} f (cos (x)) d x

\int_{1}^{e} \frac{1 + x + x ^{3}}{x} d x

\int_{1}^{3} (\frac{5}{x} - e^{- x}) d x

\int_{- 2}^{1} (2 x^{2} - 1)^{2} d x

\int_{1}^{2} e^{x - 1} d x