What is the integral from 0 to 1 of (\sqrt[3]{x}) ?

The integral from 0 to 1 of (\sqrt[3]{x}) is 3/4

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integral from 0 to 1 of (\sqrt[3]{x})

\int_{0}^{1} (3 x) d x

\frac{3}{4}

Decimal

0.75

Solution steps

\int_{0}^{1} 3 x d x

Apply the Power Rule

= [\frac{3}{4} x^{\frac{4}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{4}

= \frac{3}{4}

\int_{- 3}^{2} - 3 ∣ x ∣ d x

\int_{- 1}^{1} x^{299} d x

\int_{0}^{3} x^{2} - x d x

\int_{0}^{1} e^{2 x} x d x

\int_{- \frac{π}{3}}^{\frac{π}{3}} 6 sec^{2} (x) d x

What is the integral from 0 to 1 of (\sqrt[3]{x}) ?
The integral from 0 to 1 of (\sqrt[3]{x}) is 3/4