What is the derivative of y= 4/(x-2) ?

The derivative of y= 4/(x-2) is -4/((x-2)^2)

What is the first derivative of y= 4/(x-2) ?

The first derivative of y= 4/(x-2) is -4/((x-2)^2)

derivative of

y = \frac{4}{x - 2}

- \frac{4}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{x - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((x - 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 2 ) ^{2}} \frac{d}{d x} (x - 2)

= - \frac{1}{( x - 2 ) ^{2}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 4 (- \frac{1}{( x - 2 ) ^{2}} \cdot 1)

Simplify

4 (- \frac{1}{( x - 2 ) ^{2}} \cdot 1) : - \frac{4}{( x - 2 ) ^{2}}

= - \frac{4}{( x - 2 ) ^{2}}

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What is the derivative of y= 4/(x-2) ?
The derivative of y= 4/(x-2) is -4/((x-2)^2)
What is the first derivative of y= 4/(x-2) ?
The first derivative of y= 4/(x-2) is -4/((x-2)^2)