What is the derivative of x^2+y^2 ?

The derivative of x^2+y^2 is 2x

What is the first derivative of x^2+y^2 ?

The first derivative of x^2+y^2 is 2x

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derivative of

x^{2} + y^{2}

2 x

Solution steps

\frac{d}{d x} (x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 0

= 2 x + 0

Simplify

= 2 x

x \frac{d y}{d x} - 3 y = 7 x^{4}, y (1) = 2

f (x) = \frac{x}{x - 3}

\int ln (x^{2} - x - 6) d x

x \to 4 + lim (x + x - 4)

t - 1