integral from 1 to 8/5 of 1/(x^2)

Lösung

\int_{1}^{\frac{8}{5}} \frac{1}{x ^{2}} d x

\frac{3}{8}

Dezimale

0.375

Schritte zur Lösung

\int_{1}^{\frac{8}{5}} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= [- \frac{1}{x}]_{1}^{\frac{8}{5}}

Berechne die Grenzen:

\frac{3}{8}

= \frac{3}{8}

\int_{- 1}^{3} (\frac{x}{2} + 3) d x

\int_{- 2}^{1} [(2 - y) - y^{2}] d y

\int_{0}^{2} (4 - x^{2})^{3} d x

\int_{- 2}^{0} \frac{1}{1 - 4 x} d x

\int_{- 5}^{5} \frac{1}{x ^{2}} d x