integral from 2 to x of u^4

Lösung

\int_{2}^{x} u^{4} d u

\frac{x ^{5} - 32}{5}

Schritte zur Lösung

\int_{2}^{x} u^{4} d u

Wende die Potenzregel an

= [\frac{u ^{5}}{5}]_{2}^{x}

Berechne die Grenzen:

\frac{x ^{5}}{5} - \frac{32}{5}

= \frac{x ^{5}}{5} - \frac{32}{5}

Vereinfache

= \frac{x ^{5} - 32}{5}

\int_{0}^{1} e^{6 x - 5} d x

\int_{- 2}^{2} t^{3} (4 + t^{4})^{3} d t

\int_{2}^{3} (2 x - 3)^{4} d x

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\int_{5}^{13} x^{2} d x