integral from-1 to 1 of x^{4/3}+4x^{1/3}

Lösung

\int_{- 1}^{1} x^{\frac{4}{3}} + 4 x^{\frac{1}{3}} d x

\frac{6}{7}

Dezimale

0.85714 \dots

Schritte zur Lösung

\int_{- 1}^{1} x^{\frac{4}{3}} + 4 x^{\frac{1}{3}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{\frac{4}{3}} d x + \int_{- 1}^{1} 4 x^{\frac{1}{3}} d x

\int_{- 1}^{1} x^{\frac{4}{3}} d x = \frac{6}{7}

\int_{- 1}^{1} 4 x^{\frac{1}{3}} d x = 0

= \frac{6}{7} + 0

Vereinfache

= \frac{6}{7}

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