integral from 1 to 2 of 1/(2x)

Lösung

\int_{1}^{2} \frac{1}{2 x} d x

\frac{1}{2} ln (2)

Dezimale

0.34657 \dots

Schritte zur Lösung

\int_{1}^{2} \frac{1}{2 x} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{1}^{2} \frac{1}{x} d x

Nutze das gemeinsame Integral :

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{2} [ln ∣ x ∣]_{1}^{2}

Berechne die Grenzen:

ln (2)

= \frac{1}{2} ln (2)

\int_{- 1}^{1} (x^{4} - x^{8}) d x

\int_{0}^{4.4} 3 3 x + 4 d x

\int_{- 3}^{1} (3 - x^{2} - 2 x) d x

\int_{0}^{\frac{π}{4}} 6 x^{2} + tan (x) d x

\int_{- 1}^{1} x^{3} e^{x} d x