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人気のある微分積分 >

integral from 1 to x^2 of sec(t)

解

\int_{1}^{x^{2}} sec (t) d t

解

ln tan (x^{2}) + sec (x^{2}) - ln (tan (1) + sec (1))

解答ステップ

\int_{1}^{x^{2}} sec (t) d t

共通積分を使用する:

\int sec (t) d t = ln ∣ tan (t) + sec (t) ∣

= [ln ∣ tan (t) + sec (t) ∣]_{1}^{x^{2}}

限度を計算する:

ln tan (x^{2}) + sec (x^{2}) - ln (tan (1) + sec (1))

= ln tan (x^{2}) + sec (x^{2}) - ln (tan (1) + sec (1))

人気の例

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