integral from 0 to 3 of (x^2-4)

Lösung

\int_{0}^{3} (x^{2} - 4) d x

- 3

Schritte zur Lösung

\int_{0}^{3} x^{2} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{2} d x - \int_{0}^{3} 4 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 4 d x = 12

= 9 - 12

Vereinfache

= - 3

\int_{0}^{1} \frac{1}{x ^{\frac{5}{3}}} d x

\int_{1}^{2} x^{2} + 2 d x

\int_{0}^{4} e^{- x^{2}} d x

\int_{- 1}^{0} (1 + x) d x

\int_{- 1}^{4} (2 x + 1) d x