integral from 0 to 4 of (8x+sqrt(x))

Lösung

\int_{0}^{4} (8 x + x) d x

\frac{208}{3}

Dezimale

69.33333 \dots

Schritte zur Lösung

\int_{0}^{4} 8 x + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 8 x d x + \int_{0}^{4} x d x

\int_{0}^{4} 8 x d x = 64

\int_{0}^{4} x d x = \frac{16}{3}

= 64 + \frac{16}{3}

Vereinfache

64 + \frac{16}{3} : \frac{208}{3}

= \frac{208}{3}

\int_{- \infty}^{0} 1 d x

\int_{0}^{2} 1 + 2 x^{2} d x

\int_{0}^{2} (- t^{2} + 3 t - 2) d t

\int_{0}^{4} (8 t - 1)^{2} d t

\int_{0}^{\frac{1}{2}} \frac{1}{( x - 1 ) ( x - 2 )} d x