integral from 1 to 5 of 7-2x

Lösung

\int_{1}^{5} 7 - 2 x d x

4

Schritte zur Lösung

\int_{1}^{5} 7 - 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} 7 d x - \int_{1}^{5} 2 x d x

\int_{1}^{5} 7 d x = 28

\int_{1}^{5} 2 x d x = 24

= 28 - 24

Vereinfache

= 4

\int_{1}^{4} (1 + \frac{1}{x} + \frac{1}{x ^{2}}) d x

\int_{0}^{1} 3 x + 5 d x

\int_{0}^{t} (t - w) e^{5 w} d w

\int_{0}^{4} e^{x} x^{2} d x

\int_{0}^{2} \frac{4}{5 x + 1} d x