integral from 0 to 1 of x^2-3x+5

Lösung

\int_{0}^{1} x^{2} - 3 x + 5 d x

\frac{23}{6}

Dezimale

3.83333 \dots

Schritte zur Lösung

\int_{0}^{1} x^{2} - 3 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x - \int_{0}^{1} 3 x d x + \int_{0}^{1} 5 d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} 3 x d x = \frac{3}{2}

\int_{0}^{1} 5 d x = 5

= \frac{1}{3} - \frac{3}{2} + 5

Vereinfache

\frac{1}{3} - \frac{3}{2} + 5 : \frac{23}{6}

= \frac{23}{6}

\int_{0}^{1} x^{2} - 3 x + 6 d x

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