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Popular Calculus >

y^'=-(1+y)^4

Solution

y^{^{'}} = - (1 + y)^{4}

Solution

y = 3 \frac{1}{3 ( t + c _{1} )} - 1

Solution steps

y^{'} (t) = - (1 + y)^{4}

Solve separable ODE:

y = 3 \frac{1}{3 ( t + c _{1} )} - 1

y = 3 \frac{1}{3 ( t + c _{1} )} - 1

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-(1+y)^4 ?
The solution for y^'=-(1+y)^4 is y=\sqrt[3]{1/(3(t+c_{1))}}-1