integral from 0 to 2 of x+y

Lösung

\int_{0}^{2} x + y d y

2 x + 2

Schritte zur Lösung

\int_{0}^{2} x + y d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x d y + \int_{0}^{2} y d y

\int_{0}^{2} x d y = 2 x

\int_{0}^{2} y d y = 2

= 2 x + 2

\int_{0}^{2} (4 x - x^{2}) - (x^{2}) d x

\int_{0}^{3} \frac{1}{4} e^{- \frac{x}{4}} d x

\int_{0}^{+} 1

\int_{0}^{4} (2 x) d x

\int_{1}^{2} (\frac{3}{x} - e^{- x}) d x