integral from 0 to 3 of (4-2x)

Lösung

\int_{0}^{3} (4 - 2 x) d x

3

Schritte zur Lösung

\int_{0}^{3} 4 - 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 4 d x - \int_{0}^{3} 2 x d x

\int_{0}^{3} 4 d x = 12

\int_{0}^{3} 2 x d x = 9

= 12 - 9

Vereinfache

= 3

\int_{2}^{4} 2^{3 x} d x

\int_{0}^{6} (4 t - 1)^{2} d t

\int_{3}^{6} (2 x - 5) d x

\int_{0}^{1} \frac{1}{x ^{2} - 4 x + 5} d x

\int_{1}^{2} \frac{1}{2} y d y