What is the solution for (dy)/(dx)=((x-1))/(y-4) ?

The solution for (dy)/(dx)=((x-1))/(y-4) is y=4+sqrt(x^2-2x+c_{1)+16},y=4-sqrt(x^2-2x+c_{1)+16}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dx)=((x-1))/(y-4)

\frac{d y}{d x} = \frac{( x - 1 )}{y - 4}

y = 4 + x^{2} - 2 x + c_{1} + 16, y = 4 - x^{2} - 2 x + c_{1} + 16

Solution steps

\frac{d y}{d x} = \frac{( x - 1 )}{y - 4}

Solve separable ODE:

y = 4 + x^{2} - 2 x + c_{1} + 16, y = 4 - x^{2} - 2 x + c_{1} + 16

y = 4 + x^{2} - 2 x + c_{1} + 16, y = 4 - x^{2} - 2 x + c_{1} + 16

d er i v a t i v e y = \frac{1}{2} x + 8

f^{^{'}} (x) = x

y^{^{'}} = e^{y} 5^{x}

\int e^{- 0.08 x} d x

\frac{d}{d x} (tan^{2} (x) cos (x))

What is the solution for (dy)/(dx)=((x-1))/(y-4) ?
The solution for (dy)/(dx)=((x-1))/(y-4) is y=4+sqrt(x^2-2x+c_{1)+16},y=4-sqrt(x^2-2x+c_{1)+16}