integral from 1 to 3 of x^2ln(x)-9ln(x)

解

\int_{1}^{3} x^{2} ln (x) - 9 ln (x) d x

- 18 ln (3) + \frac{136}{9}

十進法表記

- 4.66391 \dots

解答ステップ

\int_{1}^{3} x^{2} ln (x) - 9 ln (x) d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} ln (x) d x - \int_{1}^{3} 9 ln (x) d x

\int_{1}^{3} x^{2} ln (x) d x = 9 ln (3) - \frac{26}{9}

\int_{1}^{3} 9 ln (x) d x = 9 (3 ln (3) - 2)

= 9 ln (3) - \frac{26}{9} - 9 (3 ln (3) - 2)

簡素化

9 ln (3) - \frac{26}{9} - 9 (3 ln (3) - 2) : - 18 ln (3) + \frac{136}{9}

= - 18 ln (3) + \frac{136}{9}