integral from-pi/8 to pi/(12) of cos(2x)

Lösung

\int_{- \frac{π}{8}}^{\frac{π}{12}} cos (2 x) d x

\frac{1 + 2}{4}

Dezimale

0.60355 \dots

Schritte zur Lösung

\int_{- \frac{π}{8}}^{\frac{π}{12}} cos (2 x) d x

Wende U-Substitution an

= \int_{- \frac{π}{4}}^{\frac{π}{6}} cos (u) \frac{1}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- \frac{π}{4}}^{\frac{π}{6}} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= \frac{1}{2} [sin (u)]_{- \frac{π}{4}}^{\frac{π}{6}}

Berechne die Grenzen:

\frac{1}{2} + \frac{1}{2}

= \frac{1}{2} (\frac{1}{2} + \frac{1}{2})

Vereinfache

= \frac{1 + 2}{4}

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