integral from 1 to 6 of 2x+1/x

Lösung

\int_{1}^{6} 2 x + \frac{1}{x} d x

35 + ln (6)

Dezimale

36.79175 \dots

Schritte zur Lösung

\int_{1}^{6} 2 x + \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{6} 2 x d x + \int_{1}^{6} \frac{1}{x} d x

\int_{1}^{6} 2 x d x = 35

\int_{1}^{6} \frac{1}{x} d x = ln (6)

= 35 + ln (6)

\int_{- \frac{π}{6}}^{\frac{π}{6}} 2 sec^{2} (x) d x

\int_{- 1}^{3} x^{2} + 1 d x

\int_{2}^{4} \frac{1}{x - 1} d x

\int_{0}^{6} x - 3 d x

\int_{0}^{1} x^{2} \cdot 2 x d x