integral from 0 to 4 of (4-4x)-(4-x^2)

Lösung

\int_{0}^{4} (4 - 4 x) - (4 - x^{2}) d x

- \frac{32}{3}

Dezimale

- 10.66666 \dots

Schritte zur Lösung

\int_{0}^{4} 4 - 4 x - (4 - x^{2}) d x

Vereinfache

= \int_{0}^{4} x^{2} - 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 4 x d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 4 x d x = 32

= \frac{64}{3} - 32

Vereinfache

\frac{64}{3} - 32 : - \frac{32}{3}

= - \frac{32}{3}

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